(D) To find the zeros of the polynomial $p(x)$,we set $p(x) = 0$.$3x^2 + 15x = 0$Factor out the common term $3x$:$3x(x + 5) = 0$Since $3 \neq 0$,we ha

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(D) To find the zeros of the polynomial $p(x)$,we set $p(x) = 0$.$3x^2 + 15x = 0$Factor out the common term $3x$:$3x(x + 5) = 0$Since $3 \neq 0$,we have:$x(x + 5) = 0$This implies either $x = 0$ or $x + 5 = 0$.Therefore,$x = 0$ or $x = -5$.Thus,the zeros of the quadratic polynomial $p(x)$ are $0$ and $-5$.